3=(9x)/(-9x^2)

Solution for 3=(9x)/(-9x^2) equation:

3=(9x)/(-9x^2)

We move all terms to the left:

3-((9x)/(-9x^2))=0


Domain of the equation: (-9x^2))!=0

x!=0/1

x!=0

x∈R


We multiply all the terms by the denominator


-(9x+3*(-9x^2))=0


We calculate terms in parentheses: -(9x+3*(-9x^2)), so:

9x+3*(-9x^2)

determiningTheFunctionDomain
3*(-9x^2)+9x

We multiply parentheses

-27x^2+9x

Back to the equation:

-(-27x^2+9x)


We get rid of parentheses

27x^2-9x=0

a = 27; b = -9; c = 0;
Δ = b2-4ac
Δ = -92-4·27·0
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{81}=9$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-9}{2*27}=\frac{0}{54}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+9}{2*27}=\frac{18}{54}
=1/3
$